document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607126>Question 607126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The question is how do I find (in interval notation) the values of x for which this expressio is real.\r<BR>\n" );
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document.write( "Squareroote of (15-5x).\r<BR>\n" );
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document.write( "The anwswer seems to be any number beyond 3 will produce a real number. so the answer should be (3, infinity) correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382411 by </B><A HREF=/tutors/aboutme.mpl?userid=LisaJ><B>LisaJ(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LisaJ><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That is almost correct, because x=3 is the cutoff point.  But this expression is real when x is less than or equal to 3, not when x is greater than 3.  You can see that by trying a larger number, such as x = 10. Then (15-5x) is negative, and the square root is not real.<BR>\n" );
document.write( "On the other hand, when x = 0, (15-5x) = 15, and the square root is real.<BR>\n" );
document.write( "So the answer is (-infinity, 3). </SPAN>\n" );
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