document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56389>Question 56389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y=2x-2\r<BR>\n" );
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document.write( "y=-x+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38239 by </B><A HREF=/tutors/aboutme.mpl?userid=Lacey020991><B>Lacey020991(49)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Lacey020991><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=2x-2<BR>\n" );
document.write( "y=-x+1<BR>\n" );
document.write( "I'm not sure which way your supposed to solve this, so i will show you all 3.<BR>\n" );
document.write( "Graphing:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C200%2C-5%2C5%2C-5%2C5%2C2x-2%2C-x%2B1%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C200%2C-5%2C5%2C-5%2C5%2C2x-2%2C-x%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So your answer would be (1,0)<BR>\n" );
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document.write( "By elimination, you would need to put theses equations in to standard form<BR>\n" );
document.write( "y = 2x - 2  ---- move the 2x to the other side<BR>\n" );
document.write( "-2x + y = -2 ---- this next step isnt neccesary, but i like to do it.<BR>\n" );
document.write( "2x - y = 2 <BR>\n" );
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document.write( "y = -x + 1  ---- move the x to the other side<BR>\n" );
document.write( "x + y = 1<BR>\n" );
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document.write( "You would now put these equations on top of each other and eliminate 1 variable. In this case, the y's cancel out and you dont have to multiply anything.<BR>\n" );
document.write( "2x - y = 2<BR>\n" );
document.write( " x + y = 1 <BR>\n" );
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document.write( "3x = 3<BR>\n" );
document.write( "x = 1<BR>\n" );
document.write( "Put this answer back into one of the equations. The second looks easier to me so im going to use that 1.<BR>\n" );
document.write( "x + y = 1<BR>\n" );
document.write( "1 + y = 1<BR>\n" );
document.write( "y = 0<BR>\n" );
document.write( "So your answer is (1,0)<BR>\n" );
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document.write( "To solve by substitution, you would take one of the equations and put the second in where the variable is.<BR>\n" );
document.write( "y=2x-2<BR>\n" );
document.write( "y=-x+1<BR>\n" );
document.write( "The second equation is y=... so wherever there is a y in the first equation, your going to put the second equation.<BR>\n" );
document.write( "y=2x-2<BR>\n" );
document.write( "-x + 1 = 2x - 2 ----then solve for x (isolate it)<BR>\n" );
document.write( "1 = 3x - 2<BR>\n" );
document.write( "3 = 3x<BR>\n" );
document.write( "1 = x<BR>\n" );
document.write( "Then put your answer back into one of the equations. the first looks easier to me, so im going to use that one.<BR>\n" );
document.write( "y = 2x - 2<BR>\n" );
document.write( "y = 2(1) - 2<BR>\n" );
document.write( "y = 2 - 2<BR>\n" );
document.write( "y = 0<BR>\n" );
document.write( "So again your answer would be (1,0)<BR>\n" );
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document.write( "Hope this helped!\r<BR>\n" );
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document.write( " </SPAN>\n" );
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