document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=607085>Question 607085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One angle is twice its supplement increased by 15 degrees. Find the measure of the two supplementary angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382367 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     One angle is twice its supplement increased by 15 degrees. Find the measure of the two supplementary angles.<BR>\n" );
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document.write( "Let x = supplement of angle<BR>\n" );
document.write( "then <BR>\n" );
document.write( "2x+15 = angle<BR>\n" );
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document.write( "x + 2x+15 = 180<BR>\n" );
document.write( "3x + 15 = 180<BR>\n" );
document.write( "3x = 165<BR>\n" );
document.write( "x = 55 degrees<BR>\n" );
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document.write( "other angle:<BR>\n" );
document.write( "2x+15 = 2(55)+15 = 110+15 = 125 degrees<BR>\n" );
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document.write( "answer: 55 and 125 degrees<BR>\n" );
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