document.write( "Question 607062: how do you figure out the side lengths of an equalateral triangle when given the area \n" ); document.write( "

Algebra.Com's Answer #382356 by josmiceli(19441) $\"\"$ $\"About$

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As with any triangle, $\"+A+=+%281%2F2%29%2Ab%2Ah+\"$
\n" ); document.write( "Let the sides of the equilateral triangle = $\"s\"$
\n" ); document.write( "Now the formula becomes $\"+A+=+%281%2F2%29%2As%2Ah+\"$
\n" ); document.write( "Dropping a vertical to the base forms 2 back to back
\n" ); document.write( "30-60-90 triangles.
\n" ); document.write( "Opposite the 30 is $\"+s%2F2+\"$
\n" ); document.write( "Opposite the 60 is $\"+%28s%2F2%29%2Asqrt%283%29+\"$
\n" ); document.write( "Opposite the 90 is $\"+s+\"$
\n" ); document.write( "The vertical, $\"h\"$ , is opposite the 60 degree angle, so
\n" ); document.write( " $\"+A+=+%281%2F2%29%2As%2A%28s%2F2%29%2Asqrt%283%29+\"$
\n" ); document.write( " $\"+A+=+%28s%5E2%2F4%29%2Asqrt%283%29+\"$
\n" ); document.write( " $\"+A+=+%28s%2F2%29%5E2%2Asqrt%283%29+\"$
\n" ); document.write( " \n" ); document.write( "

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