document.write( "Question 607041: I need to find the oblique asymptote for (x^3-9x)/(x^2+x-20) \n" ); document.write( "
Algebra.Com's Answer #382349 by lwsshak3(11628)\"\" \"About 
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I need to find the oblique asymptote for (x^3-9x)/(x^2+x-20)
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\n" ); document.write( "When degree of numerator is one higher than that of the denominator, you will have an oblique asymptote.
\n" ); document.write( "To find the oblique asymptote, divide numerator by denominator.(by long division)
\n" ); document.write( "........................x..... -1.............................
\n" ); document.write( "....x^2+x-20 ) x^3 +0.... +9x .......................
\n" ); document.write( "........................x^3 +x^2-20x..................................
\n" ); document.write( "...............................-x^2-11x..........................
\n" ); document.write( "...............................-x^2 -x+20..........................
\n" ); document.write( "..................................... -10x-20..................
\n" ); document.write( "You will get an answer=(x-1)+remainder(10x-20)
\n" ); document.write( "Equation of oblique asymptote: y=x-1
\n" ); document.write( "see graph below:
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