document.write( "Question 607029: So there are three seats, each one can either be filled by a boy or a girl. How many different combinations are there with repetition? \r
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document.write( "I know that there are 4:\r
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document.write( "BBB
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document.write( "BBG
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document.write( "BGG
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document.write( "GGG\r
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document.write( "However, I don't know the equation to find this... Could you help? Much obliged! \n" );
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Algebra.Com's Answer #382338 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! There are 2^3 = 8 ways to fill 3 seats with either a boy or a girl. Since order doesn't matter (and something like BBG = BGB and BBG = GBB), we're over-counting and need to divide by 2! = 2*1 = 2 to get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "8/2 = 4\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |