document.write( "Question 606659: Solve square root of 2x+3- square root of x+1=1 \n" ); document.write( "
Algebra.Com's Answer #382331 by ankor@dixie-net.com(22740)\"\" \"About 
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Solve square root of 2x+3- square root of x+1=1
\n" ); document.write( ":
\n" ); document.write( "\"sqrt%282x%2B3%29-sqrt%28x%2B1%29+=+1\"
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\n" ); document.write( "\"sqrt%282x%2B3%29+=+sqrt%28x%2B1%29+%2B+1\"
\n" ); document.write( "Square both sides, you have to FOIL the right side
\n" ); document.write( "2x + 3 = \"%28x%2B1%29+%2B+2sqrt%28x%2B1%29+%2B+1\"
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\n" ); document.write( "2x + 3 = x + 2 + \"2sqrt%28x%2B1%29\"
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\n" ); document.write( "2x - x + 3 - 2 = \"2sqrt%28x%2B1%29\"
\n" ); document.write( ":
\n" ); document.write( "(x + 1) = \"2sqrt%28x%2B1%29\"
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\n" ); document.write( "Square both sides, FOIL the left side
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\n" ); document.write( "x^2 + 2x + 1 = 4(x+1)
\n" ); document.write( "x^2 + 2x + 1 = 4x + 4
\n" ); document.write( "x^2 + 2x - 4x + 1 - 4 = 0
\n" ); document.write( "x^2 - 2x - 3 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-3)(x+1) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 3
\n" ); document.write( "x = -1
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\n" ); document.write( "We have to check both solutions in the original equation
\n" ); document.write( "x = -1 will not work, it would give us a neg value inside the radical
\n" ); document.write( "Try x = 3
\n" ); document.write( "\"sqrt%286%2B3%29-sqrt%283%2B1%29+=+1\"; looks OK, x=3 is our solution \n" ); document.write( "
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