document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56306>Question 56306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangular region with the maximum area that can be enclosed by 60 feet of fencing. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38230 by </B><A HREF=/tutors/aboutme.mpl?userid=Cintchr><B>Cintchr(481)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cintchr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = 2(l+w) = 60  ..... A = l * w<BR>\n" );
document.write( "Possible dimensions are ....<BR>\n" );
document.write( "Perimiter ....... Area <BR>\n" );
document.write( "2(1+29) ......... 1 * 29 = 29<BR>\n" );
document.write( "2(2+28) ......... 2 * 28 = 56<BR>\n" );
document.write( "2(3+27) ......... 3 * 27 = 81<BR>\n" );
document.write( "etc ....<BR>\n" );
document.write( "notice that the area goes up as you move from a rectangle to a square ...<BR>\n" );
document.write( "so if the perimiter is 60 ... then it CAN be a square.<BR>\n" );
document.write( "2(15+15) ........ 15 * 15 = 225 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );