document.write( "Question 56362: The length of a rectangle is 2cm more tham twice its width. If the perimeter of the rectangle is 52cm find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #38228 by Cintchr(481)\"\" \"About 
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P = 2(l+w)
\n" ); document.write( "l = 2w + 2
\n" ); document.write( "\"+P+=+2%28l%2Bw%29+\"
\n" ); document.write( "Substitute the valuse for the perimiter and the length into the equation so that you are dealing with only one variable
\n" ); document.write( "\"+52+=+2%282w+%2B2+%2B+w%29+\"
\n" ); document.write( "combine like terms
\n" ); document.write( "\"+52+=+2%283w+%2B2%29+\"
\n" ); document.write( "distribute
\n" ); document.write( "\"+52+=+6w+%2B+4+\"
\n" ); document.write( "subtract 4 from both sides
\n" ); document.write( "\"+48+=+6w+\"
\n" ); document.write( "divide by 6
\n" ); document.write( "\"+8+=+w+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+l+=+2w+%2B+2+\"
\n" ); document.write( "Plug in w=8
\n" ); document.write( "\"+l+=+2%288%29+%2B+2+\"
\n" ); document.write( "\"+l+=+16+%2B+2+\"
\n" ); document.write( "\"+l+=+18+\"\r
\n" ); document.write( "\n" ); document.write( "
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