document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=606856>Question 606856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am a 4 digit number greater than 9,000.<BR>\n" );
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document.write( "My hundreds digit is twice my ones digit.<BR>\n" );
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document.write( "My ones digit is greater than my tens digit.<BR>\n" );
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document.write( "The sum of my digits is 20.<BR>\n" );
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document.write( "What number am I? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382279 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose the number is 9abc\r<BR>\n" );
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document.write( "We know that a = 2c, c > b. Also, 9+a+b+c = 20, so a+b+c = 11. We can assume c = 0, c = 1, c = 2, etc. and find all the possible triples (a,b,c):\r<BR>\n" );
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document.write( "c = 0 --> a = 0, b = 11<BR>\n" );
document.write( "c = 1 --> a = 2, b = 8<BR>\n" );
document.write( "c = 2 --> a = 4, b = 5<BR>\n" );
document.write( "c = 3 --> a = 6, b = 2\r<BR>\n" );
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document.write( "The first three cases don't work, because b > 9, or b is greater than c. The third case does work, so (a,b,c) = (6,2,3) and the number is 9623. </SPAN>\n" );
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