document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=606795>Question 606795</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely <BR>\n" );
document.write( "100-c^6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382253 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 100\ -\ c^6\">\r<BR>\n" );
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document.write( "Factor the difference of two squares:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ (10\ +\ c^3)(10\ -\ c^3)\">\r<BR>\n" );
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document.write( "Bearing in mind that the cube root of 10 cubed is 10, factor the sum and difference of two cubes:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(\sqrt[3]{10}\ +\ c\right) \left(\sqrt[3]{100}\ -\ c\sqrt[3]{10}\ +\ c^2\right)\left(\sqrt[3]{10}\ -\ c\right)\left(\sqrt[3]{100}\ +\ c\sqrt[3]{10}\ +\ c^2\right)\">\r<BR>\n" );
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document.write( "You can also apply the quadratic formula to the two trinomials and get the following result:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(\sqrt[3]{10}\ +\ c\right) \left(c\ -\ \frac{c\sqrt[3]{10}\ +\ \sqrt{c^2\sqrt[3]{100}\ -\ 4\sqrt[3]{100}}}{2}\right)\left(c\ -\ \frac{c\sqrt[3]{10}\ -\ \sqrt{c^2\sqrt[3]{100}\ -\ 4\sqrt[3]{100}}}{2}\right)\cdots\\ \ \ \ \ \ \ \ \ \ \ \cdots \left(\sqrt[3]{10}\ -\ c\right) \left(c\ -\ \frac{-c\sqrt[3]{10}\ +\ \sqrt{c^2\sqrt[3]{100}\ -\ 4\sqrt[3]{100}}}{2}\right)\left(c\ -\ \frac{-c\sqrt[3]{10}\ -\ \sqrt{c^2\sqrt[3]{100}\ -\ 4\sqrt[3]{100}}}{2}\right)\">\r<BR>\n" );
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document.write( "Which is the end because you started with a 6th degree polynomial and ended with 6 first degree binomial factors.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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