document.write( "Question 606723: Can you help me solve 2^2x+1=15 for x. \n" ); document.write( "
Algebra.Com's Answer #382240 by lwsshak3(11628) ![]() You can put this solution on YOUR website! 2^2x+1=15 for x \n" ); document.write( "2^2x=14 \n" ); document.write( "2xlog2=log14 \n" ); document.write( "x=log14/(2log2) \n" ); document.write( "x≈1.9037 \n" ); document.write( " |