document.write( "Question 606723: Can you help me solve 2^2x+1=15 for x. \n" ); document.write( "
Algebra.Com's Answer #382240 by lwsshak3(11628)\"\" \"About 
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2^2x+1=15 for x
\n" ); document.write( "2^2x=14
\n" ); document.write( "2xlog2=log14
\n" ); document.write( "x=log14/(2log2)
\n" ); document.write( "x≈1.9037
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