document.write( "Question 606720: Please help me solve this:\r
\n" ); document.write( "\n" ); document.write( "log(x-3)=1-log(x)
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Algebra.Com's Answer #382226 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Please help me solve this:
\n" ); document.write( "log(x-3)=1-log(x)
\n" ); document.write( "log(x-3)+log(x)=1
\n" ); document.write( "place under single log
\n" ); document.write( "log[(x-3)*x]=1
\n" ); document.write( "convert to exponential form
\n" ); document.write( "10^1=x(x-3)=10
\n" ); document.write( "x^2-3x-10=0
\n" ); document.write( "(x-5)(x+2)=0
\n" ); document.write( "x=-2 (reject, x>0)
\n" ); document.write( "or
\n" ); document.write( "x=5
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