document.write( "Question 56354This question is from textbook algebra 2 equations graphs applications
\n" ); document.write( ": hello,
\n" ); document.write( " were solving linear equations by graphing, and i am having a little troble with this problem, -8x+12y=48 2x-3y=6. when i solve for the variables i get (-6,4) and (3,-2) so the lines are parallel, but my teacher informed me that the lines are not supposed to parallel. i am very confused and any help would be greatly appriciated. thank you very much!
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Algebra.Com's Answer #38221 by Cintchr(481)\"\" \"About 
You can put this solution on YOUR website!
\"+-8x%2B12y=48\" and \"+2x-3y=6+\"
\n" ); document.write( "get both equations in y=mx+b (point-slope form)
\n" ); document.write( "\"+12y+=+8x+%2B48+\" and \"+-3y+=-2x+%2B6+\"
\n" ); document.write( "divide the first by 12 and divide the second by -3
\n" ); document.write( "\"+y+=+8x%2F12+%2B48%2F12+\" and \"+y+=-2x%2F-3+%2B6%2F-3+\"
\n" ); document.write( "Reduce the fractions
\n" ); document.write( "\"+y+=+2x%2F3+%2B+4+\" and \"+y+=2x%2F3+-2+\"
\n" ); document.write( "Notice how the m value IS exactly the same. so assuming your wrote the problem correctly .. they ARE parallel.
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+%282x%2F3%29%2B4%2C+%282x%2F3%29-2+%29+\"\r
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