document.write( "Question 606686: How do I solve:\r
\n" ); document.write( "\n" ); document.write( " $\"4%5E%283x-1%29=12\"$ \n" ); document.write( "

Algebra.Com's Answer #382166 by mathie123(224) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"4%5E%283x-1%29=12\"$
\n" ); document.write( "If you have a variable in the exponent, we always want to take logs of both sides:
\n" ); document.write( " $\"log%284%5E%283x-1%29%29=log%2812%29\"$
\n" ); document.write( "Now we can bring down the exponent using our log rules:
\n" ); document.write( " $\"%283x-1%29log%284%29=log%2812%29\"$
\n" ); document.write( "And isolate for x
\n" ); document.write( " $\"%283x-1%29=log%2812%29%2F%28log%284%29%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I will leave the rest of the isolating up to you. (Don't forget that log of a number is just a number itself, so don't let that fool you) \n" ); document.write( "

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