document.write( "Question 606578: x=w/8+y/8+z/8
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Algebra.Com's Answer #382123 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
To make things a little easier, let's first get rid of the denominators by multiplying both sides of the equations (all terms) by 8 to get:
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\n" ); document.write( "\"8x+=+%288%2Aw%29%2F8%2B%288%2Ay%29%2F8+%2B+%288%2Az%29%2F8\"
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\n" ); document.write( "Where an 8 appears in the numerator, it cancels with the 8 in the denominator:
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\n" ); document.write( "and we are left with:
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\n" ); document.write( "\"8x+=+w+%2B+y+%2B+z\"
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\n" ); document.write( "Now we want to get y by itself on one side of the equation and everything else on the other side. To do that we can subtract w and z from both sides of the equation:
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\n" ); document.write( "\"8x+-+w+-+z+=+w+%2B+y+%2B+z+-+w+-+z\"
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\n" ); document.write( "On the right side the w and the minus w cancel each other and also the z and the minus z cancel each other, and we are left with just y. So the equation is reduced to:
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\n" ); document.write( "\"8x+-+w+-+z+=+y\"
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\n" ); document.write( "Just transpose this (switch sides) to get it into the conventional form:
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\n" ); document.write( "\"y+=+8x+-+w+-+z\"
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\n" ); document.write( "And that's the answer to this problem. We have solved for y in terms of the other variables in the equation.
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\n" ); document.write( "Hope this helps you to understand what you were asked to do and how you would go about doing it.
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