document.write( "Question 606133: how to graph x=y^2-6y+8 This is parabola
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Algebra.Com's Answer #382122 by lwsshak3(11628)\"\" \"About 
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how to graph
\n" ); document.write( "x=y^2-6y+8
\n" ); document.write( "complete the square
\n" ); document.write( "x=(y^2-6y+9)+8-9
\n" ); document.write( "x=(y-3)^2-1
\n" ); document.write( "This is a parabola that opens rightwards
\n" ); document.write( "vertex: (-1,3)
\n" ); document.write( "x-intercept
\n" ); document.write( "set y=0
\n" ); document.write( "x=8
\n" ); document.write( "see graph below:
\n" ); document.write( "y=±(x+1)^.5+3
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