document.write( "Question 606501: Graph:\r
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document.write( "y^2/25-x^2/4=1 \n" );
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Algebra.Com's Answer #382118 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Graph: \n" ); document.write( "y^2/25-x^2/4=1 \n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis. y-term leads \n" ); document.write( "Its standard form: (y-k)^2/a^2-(x-h)^2/b^2=1, (h,k)=(x,y) coordinates of center \n" ); document.write( "For given equation: \n" ); document.write( "center: (0,0) \n" ); document.write( "a^2=25 \n" ); document.write( "a=5 \n" ); document.write( "vertices: (0,0±a)=(0,0±5)=(0,-5) and (0,5) \n" ); document.write( ".. \n" ); document.write( "b^2=4 \n" ); document.write( "b=2 \n" ); document.write( "length of conjugate axis=2b=4 \n" ); document.write( "see graph below: \n" ); document.write( "y=±(25+25x^2/4)^.5 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |