document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=606483>Question 606483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the following general form of a circle, find the value of \"a\" if the center is at (1/3, 4/3).  Use this value of \"a\" to find the radius of a circle.  Make sure to write it in simplified rationalized form.<BR>\n" );
document.write( "3x^2-2x+3y^2-ay-27=0<BR>\n" );
document.write( "I know you would group it just as you would any other equation when you are going from general to standard, but I am confused as to what to do with the -ay.  Help please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #382117 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=382117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the following general form of a circle, find the value of \"a\" if the center is at (1/3, 4/3). Use this value of \"a\" to find the radius of a circle. Make sure to write it in simplified rationalized form.<BR>\n" );
document.write( "3x^2-2x+3y^2-ay-27=0<BR>\n" );
document.write( "complete the square<BR>\n" );
document.write( "3(x^2-2x/3+1/9)+3(y^2-ay+a^2/4)=27+1/3+3/2=27+11/6<BR>\n" );
document.write( "3(x-1/3)^2+3(y-a/2)^2=173/6<BR>\n" );
document.write( "a/2=4/3<BR>\n" );
document.write( "a=8/3<BR>\n" );
document.write( "equation of given circle:<BR>\n" );
document.write( "3(x-1/3)^2+3(y-4/3)^2=173/6<BR>\n" );
document.write( "radius^2=173/6<BR>\n" );
document.write( "radius=&#8730;(173/6)=&#8730;1038/6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );