document.write( "Question 56339: McGraw Hill 6th edition, 8.3 # 58.
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document.write( "Thank you so very much for your time!!!!
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document.write( "The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34, find the dimensions of the rectangle. \n" );
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Algebra.Com's Answer #38211 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34, find the dimensions of the rectangle. \n" ); document.write( "---------- \n" ); document.write( "Let the width be \"w\" \n" ); document.write( "Then the length is \"2w+2\" \n" ); document.write( "Perimeter = 2(length + width) \n" ); document.write( "34=2(w+2w+2) \n" ); document.write( "17=3w+2 \n" ); document.write( "15=3w \n" ); document.write( "w=5 (width is 5 inches) \n" ); document.write( "length = 2w+2=12 inches \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |