document.write( "Question 606526: Terri and Juan earned $1,150 from a one-year investment of $15,000. If Terri invested some of the money at 8% interest and Juan invested the rest at 7%, how much did each invest? \n" ); document.write( "
Algebra.Com's Answer #382096 by mananth(16949)\"\" \"About 
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Terri 8.00%per annum ------------- Amount invested =x
\n" ); document.write( "Juan 7.00%per annum ------------ Amount invested = y
\n" ); document.write( " 15000
\n" ); document.write( "Interest----- 1150
\n" ); document.write( "Sum of investments
\n" ); document.write( "x + y= 15000 -------------1
\n" ); document.write( "Interest earned on both investments
\n" ); document.write( "8.00% x + 7.00% y= 1150
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8 x + 7 y= 115000.00 --------2
\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
\n" ); document.write( "-8 x -8 y= -120000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -1 y= -5000
\n" ); document.write( "divide by -1
\n" ); document.write( " y = 5000
\n" ); document.write( "Terri 7.00% $ 5000
\n" ); document.write( "Juan 8.00% $ 10000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "5000 --------- 7.00% ------- 350.00
\n" ); document.write( "10000 ------------- 8.00% ------- 800.00
\n" ); document.write( "Total -------------------- 1150.00
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\n" ); document.write( "m.ananth@hotmail.ca
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