document.write( "Question 606313: Jim traveled 240 miles to a convention. Later, his wife Ann drove up to meet him. Ann's average speed exceeded Jim's by 4 mph, and the trip took her 15 minutes less time. Find Ann's speed. \n" ); document.write( "
Algebra.Com's Answer #382022 by vksarvepalli(154)\"\" \"About 
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Let the average speed of Jim be 'x' mph
\n" ); document.write( "so the average speed of Ann will be 'x+4' mph\r
\n" ); document.write( "\n" ); document.write( "let time taken by Jim to travel is 't' hrs.
\n" ); document.write( "then the time taken by Ann will be 't-0.25' hrs. (Since 15 mins = .25 hrs)\r
\n" ); document.write( "\n" ); document.write( "Now, average speed = total distance travelled / total time taken.\r
\n" ); document.write( "\n" ); document.write( " so, x = 240/t --- eq.1\r
\n" ); document.write( "\n" ); document.write( " x+4 = 240/(t-0.25) -----eq.2\r
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\n" ); document.write( "\n" ); document.write( "Substituting eq.1 in eq.2\r
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\n" ); document.write( "\n" ); document.write( "we get (240/t) + 4 = 240/(t-0.25) \r
\n" ); document.write( "\n" ); document.write( " => 1/t + 1/60 = 1/(t-0.25)
\n" ); document.write( " => 1/(t-0.25) - 1/t = 1/60
\n" ); document.write( " => 4t^2-t-60 = 0\r
\n" ); document.write( "\n" ); document.write( " So t= 4 or t= -15/4\r
\n" ); document.write( "\n" ); document.write( "since time cannot be a negative value.\r
\n" ); document.write( "\n" ); document.write( " t = 4 hrs.
\n" ); document.write( "from eq.1 x = 240/t = 240/4 = 60 mph\r
\n" ); document.write( "\n" ); document.write( " So, Ann's speed = x+4 = 60+4 = 64 mph\r
\n" ); document.write( "\n" ); document.write( "Ans: 64 mph
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