document.write( "Question 602054: How do I solve 12e^(4x-3)=72 \n" ); document.write( "
Algebra.Com's Answer #381937 by lwsshak3(11628)\"\" \"About 
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How do I solve
\n" ); document.write( "12e^(4x-3)=72
\n" ); document.write( "e^(4x-3)=72/12=6
\n" ); document.write( "take log of both sides
\n" ); document.write( "(4x-3)lne=ln6
\n" ); document.write( "lne=1 (log of base=1)
\n" ); document.write( "4x-3=ln6
\n" ); document.write( "4x=ln6+3
\n" ); document.write( "x=(ln6+3)/4
\n" ); document.write( "x≈1.1979
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