document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56296>Question 56296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me.\r<BR>\n" );
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document.write( "Solve by completing the square.<BR>\n" );
document.write( "2x^2+10x+11=0\r<BR>\n" );
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document.write( "I get-5+-sqrt23/2\r<BR>\n" );
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document.write( "not sure how I got there.  Is it right?  How should I work it out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38190 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38190\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square.<BR>\n" );
document.write( "2x^2+10x+11=0 <BR>\n" );
document.write( "x^2+5x+? = -11/2 +?<BR>\n" );
document.write( "x^2+5x+(5/2)^2 = (-11/2)+(25/4)<BR>\n" );
document.write( "(x+(5/2))^2 = 3/4<BR>\n" );
document.write( "Take the square root of both sides to get:<BR>\n" );
document.write( "x+(5/2)=+- (1/2)sqrt3<BR>\n" );
document.write( "x= -(5/2)+-(1/2)sqrt3<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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