document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=605186>Question 605186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify in terms of a single logarithm with base 4 <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+log+to+the+base+2+of+%28x%29-+log+to+the+base+2+of+%282%2Fy%29%2B+log+to+the+base+8+of+%28sqrt%28+y+%29%29-+log+to+the+base+16+of+%28z%5E2%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381899 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> simplify in terms of a single logarithm with base 4. log to the base 2 of (x)- log to the base 2 of (2/y)+ log to the base 8 of (sqrt( y ))- log to the base 16 of (z^2) <BR>\n" );
document.write( "**<BR>\n" );
document.write( "log4(x)/log4(2)-log4(2/y)/log4(2)+log4&#8730;y/log4(8)-log4(z^2)/log4(16)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "log4(2)=1/2<BR>\n" );
document.write( "log4(8)=3/2<BR>\n" );
document.write( "log4(16)=4<BR>\n" );
document.write( "..<BR>\n" );
document.write( "log4(x)/(1/2)-log4(2/y)/(1/2)+log4&#8730;y/(3/2)-log4(z^2)/4<BR>\n" );
document.write( "2log4(x)-2log4(2/y)+(2/3)log4&#8730;y-4log4(z^2)<BR>\n" );
document.write( "rearrange terms<BR>\n" );
document.write( "2log4(x)+(2/3)log4&#8730;y-(2log4(2/y)+4log4(z^2))<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log4[x^2*y^(1/3)/(2/y)^2*z^8] </SPAN>\n" );
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