document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=605985>Question 605985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question One:<BR>\n" );
document.write( "Scores on a test are normally distributed with a mean of 541 and a standard deviation of 120. Use the 68-95-99.7 Rule to find the percentage of people taking the test who score below 181. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381898 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381898\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Scores on a test are normally distributed with a mean of 541 and a standard deviation of 120. Use the 68-95-99.7 Rule to find the percentage of people taking the test who score below 181.<BR>\n" );
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document.write( "Find the number of standard deviations 181 is to the left of the mean:<BR>\n" );
document.write( "(541-181)/120 = 3<BR>\n" );
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document.write( "Draw a normal curve.<BR>\n" );
document.write( "According to the \"Rule\" only 0.3% of the people are <BR>\n" );
document.write( "outside the 99.7% limits.<BR>\n" );
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document.write( "Only 0.3%2  =  0.15% or 0.0015 of the people are below 181.<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );