document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=605353>Question 605353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log base4(7x-8)=log base4(5x+3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381894 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381894\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log base4(7x-8)=log base4(5x+3)<BR>\n" );
document.write( "log4(7x-8)-log4(5x+3)=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log[(7x-8)/(5x+3)]=0<BR>\n" );
document.write( "convert to exponential form: base(4) raised to log of number(0)=number[(7x-8)/(5x+3)]<BR>\n" );
document.write( "4^0=[(7x-8)/(5x+3)]=1<BR>\n" );
document.write( "7x-8=5x+3<BR>\n" );
document.write( "2x=11<BR>\n" );
document.write( "x=5.5 </SPAN>\n" );
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