document.write( "Question 605977: two supplementary angles are in the ratio 7:2 how many degrees are there in the measure of the larger angle? \n" ); document.write( "
Algebra.Com's Answer #381870 by Sarey(4)\"\" \"About 
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(1)
\n" ); document.write( "Let x - no of degrees in the smaller angle
\n" ); document.write( "Therefore 2x the no of degrees in the larger angle
\n" ); document.write( "Therefore 2x + x = 180 and hence x = 60 degrees and the greater angle is 2*60 = 120 deg.
\n" ); document.write( "(2)
\n" ); document.write( "180 = x + (x - 20) = 2x - 20
\n" ); document.write( "2x = 200
\n" ); document.write( "x = 100
\n" ); document.write( "Thus 100 is one angle and 80 is the second angle
\n" ); document.write( "80 deg is the answer to your question.\r
\n" ); document.write( "\n" ); document.write( "(3)
\n" ); document.write( "7x + 2x = 180
\n" ); document.write( "9x = 180
\n" ); document.write( "x = 20
\n" ); document.write( "One angle is 7*20 = 140 deg
\n" ); document.write( "The other angle is 2*20 = 40 deg
\n" ); document.write( "and 140 + 40 = 180 deg\r
\n" ); document.write( "\n" ); document.write( "(4)
\n" ); document.write( "(3a + 10) + (2a - 40) = 5a - 30 = 180
\n" ); document.write( "and 5a = 180 + 30 = 210
\n" ); document.write( "a = 42
\n" ); document.write( "The angles are 3*42 + 10 = 126 + 10 = 136 deg
\n" ); document.write( "and 2*42 - 40 = 84 - 40 = 44 deg
\n" ); document.write( "Add the angles 136 + 44 = 180
\n" ); document.write( "The smaller angle is 44 degrees\r
\n" ); document.write( "\n" ); document.write( "(5)
\n" ); document.write( "Let the measure of the angle you seek be 'x'
\n" ); document.write( "2x = twice the angle
\n" ); document.write( "The angle which is 60 more than twice the angle = {60 + 2x}
\n" ); document.write( "Therefore x + {60 +2x} = 180
\n" ); document.write( "3x + 60 =180
\n" ); document.write( "3x = 120
\n" ); document.write( "x = 40 deg is the answer;\r
\n" ); document.write( "\n" ); document.write( "check 2*40 = 80
\n" ); document.write( "2*40 + 60 = 140
\n" ); document.write( "and 40 + 140 = 180 ok\r
\n" ); document.write( "\n" ); document.write( "(6)
\n" ); document.write( "Let x = one angle
\n" ); document.write( "Let x + 80 the other angle
\n" ); document.write( "Thus x + {x + 80} = 2x + 80 = 180
\n" ); document.write( "2x = 100
\n" ); document.write( "x = 50
\n" ); document.write( "Thus one angle = 50 and
\n" ); document.write( "the other angle = 130 deg which is the answer\r
\n" ); document.write( "\n" ); document.write( "(7)
\n" ); document.write( "Let the sought angle be 'x' and its supplement is {180 - x}
\n" ); document.write( "The compliment of 'x' is {90 - x}
\n" ); document.write( "We are told that {180 - x} - 5*{90 - x} = 10
\n" ); document.write( "180 - x - 450 + 5x = 10
\n" ); document.write( "4x = 10 + 450 - 180 = 460 - 180 = 280
\n" ); document.write( "x = 70 degrees which is the answer to the question\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "supplement = 180 - 70 = 110
\n" ); document.write( "compliment = 90 - 70 = 20
\n" ); document.write( "Five times the compliment = 5*20 = 100
\n" ); document.write( "supplement - 5*compliment =
\n" ); document.write( "110 - 100 = 10 ok
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