document.write( "Question 605977: two supplementary angles are in the ratio 7:2 how many degrees are there in the measure of the larger angle? \n" ); document.write( "
Algebra.Com's Answer #381870 by Sarey(4)![]() ![]() ![]() You can put this solution on YOUR website! (1) \n" ); document.write( "Let x - no of degrees in the smaller angle \n" ); document.write( "Therefore 2x the no of degrees in the larger angle \n" ); document.write( "Therefore 2x + x = 180 and hence x = 60 degrees and the greater angle is 2*60 = 120 deg. \n" ); document.write( "(2) \n" ); document.write( "180 = x + (x - 20) = 2x - 20 \n" ); document.write( "2x = 200 \n" ); document.write( "x = 100 \n" ); document.write( "Thus 100 is one angle and 80 is the second angle \n" ); document.write( "80 deg is the answer to your question.\r \n" ); document.write( "\n" ); document.write( "(3) \n" ); document.write( "7x + 2x = 180 \n" ); document.write( "9x = 180 \n" ); document.write( "x = 20 \n" ); document.write( "One angle is 7*20 = 140 deg \n" ); document.write( "The other angle is 2*20 = 40 deg \n" ); document.write( "and 140 + 40 = 180 deg\r \n" ); document.write( "\n" ); document.write( "(4) \n" ); document.write( "(3a + 10) + (2a - 40) = 5a - 30 = 180 \n" ); document.write( "and 5a = 180 + 30 = 210 \n" ); document.write( "a = 42 \n" ); document.write( "The angles are 3*42 + 10 = 126 + 10 = 136 deg \n" ); document.write( "and 2*42 - 40 = 84 - 40 = 44 deg \n" ); document.write( "Add the angles 136 + 44 = 180 \n" ); document.write( "The smaller angle is 44 degrees\r \n" ); document.write( "\n" ); document.write( "(5) \n" ); document.write( "Let the measure of the angle you seek be 'x' \n" ); document.write( "2x = twice the angle \n" ); document.write( "The angle which is 60 more than twice the angle = {60 + 2x} \n" ); document.write( "Therefore x + {60 +2x} = 180 \n" ); document.write( "3x + 60 =180 \n" ); document.write( "3x = 120 \n" ); document.write( "x = 40 deg is the answer;\r \n" ); document.write( "\n" ); document.write( "check 2*40 = 80 \n" ); document.write( "2*40 + 60 = 140 \n" ); document.write( "and 40 + 140 = 180 ok\r \n" ); document.write( "\n" ); document.write( "(6) \n" ); document.write( "Let x = one angle \n" ); document.write( "Let x + 80 the other angle \n" ); document.write( "Thus x + {x + 80} = 2x + 80 = 180 \n" ); document.write( "2x = 100 \n" ); document.write( "x = 50 \n" ); document.write( "Thus one angle = 50 and \n" ); document.write( "the other angle = 130 deg which is the answer\r \n" ); document.write( "\n" ); document.write( "(7) \n" ); document.write( "Let the sought angle be 'x' and its supplement is {180 - x} \n" ); document.write( "The compliment of 'x' is {90 - x} \n" ); document.write( "We are told that {180 - x} - 5*{90 - x} = 10 \n" ); document.write( "180 - x - 450 + 5x = 10 \n" ); document.write( "4x = 10 + 450 - 180 = 460 - 180 = 280 \n" ); document.write( "x = 70 degrees which is the answer to the question\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "supplement = 180 - 70 = 110 \n" ); document.write( "compliment = 90 - 70 = 20 \n" ); document.write( "Five times the compliment = 5*20 = 100 \n" ); document.write( "supplement - 5*compliment = \n" ); document.write( "110 - 100 = 10 ok \n" ); document.write( " |