document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=605984>Question 605984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need help step by step to find the solution to the equation 3=Square 9-x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381868 by </B><A HREF=/tutors/aboutme.mpl?userid=Sarey><B>Sarey(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Sarey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor x-9 into (sqrt x + 3)(sqrt x - 3)<BR>\n" );
document.write( "Then cancel the opposite factors, leaving a -1 in place and you have\r<BR>\n" );
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document.write( "lim as x->9 of -(sqrt x + 3)\r<BR>\n" );
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document.write( "Plug in 9 for x and you have -(3+3) = -6<BR>\n" );
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