document.write( "Question 605863: A ball is thrown upward with a velociity of 80ft/s from a height of 576ft. H= -16t^2+80t=576 gives the height,h, after t sec. Find the time when the ball is 300ft above the ground. H value is 300\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "OK--I know how that I have to set it to zero by subtracting 300 from 576. It will not factor out evenly. After setting it up with the quadratic formula, I am still getting it wrong. Please help me. I am on my 5th problem like this and am severly struggleing.
\n" ); document.write( "

Algebra.Com's Answer #381841 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"H=+-16t%5E2%2B80t%2B576\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"300+=+-16t%5E2%2B80t%2B576\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0+=+-16t%5E2%2B80t%2B576-300\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0+=+-16t%5E2%2B80t%2B276\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-16t%5E2%2B80t%2B276+=+0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"16t%5E2-80t-276+=+0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to solve\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+%28-%28-80%29%2B-sqrt%28%28-80%29%5E2-4%2816%29%28-276%29%29%29%2F%282%2816%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+%2880%2B-sqrt%286400-%28-17664%29%29%29%2F%2832%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+%2880%2B-sqrt%2824064%29%29%2F32\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+%2880%2Bsqrt%2824064%29%29%2F32\" or \"t+=+%2880-sqrt%2824064%29%29%2F32\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+%2880%2B16%2Asqrt%2894%29%29%2F32\" or \"t+=+%2880-16%2Asqrt%2894%29%29%2F32\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+%285%2Bsqrt%2894%29%29%2F2\" or \"t+=+%285-sqrt%2894%29%29%2F2\" <--- Exact Solutions\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+7.34767985741632\" or \"t+=+-2.34767985741632\" <--- Approximate Solutions\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We now ignore the negative solution since a negative time value doesn't make any sense.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the ball is 300 ft above the ground at approximately 7.34767985741632 seconds
\n" ); document.write( "
\n" );