document.write( "Question 605875: My exam was 42 questions and if I got 3 or 4 questions wrong what would I get? It was out of 100%\r
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document.write( "Thank you so much banessa:) \n" );
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Algebra.Com's Answer #381833 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! If you got 4 questions wrong (imagine the worse case of the two), then you got 42 - 4 = 38 questions correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So your grade would then be (38/42)*100 = 0.90476*100 = 90.476%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you got 3 wrong, then your score would be greater than what's highlighted above. \n" ); document.write( " |