document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=605848>Question 605848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the sum of each.<BR>\n" );
document.write( " 2.3+2.6+2.9+....; 40th term </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381825 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is an arithmetic sequence with common difference = 0.3<BR>\n" );
document.write( "The nth term of this sequence can be written a(n) = a + 0.3*(n-1), where a = the 1st term<BR>\n" );
document.write( "So a(40) = 2.3 + 0.3(39) = 14<BR>\n" );
document.write( "The sum of the first 40 terms is S(40) = (40/2)(a + a(40)) = 20(2.3+14) = 326<BR>\n" );
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