document.write( "Question 56254: please solve the system
\n" ); document.write( "3x+4y=-2
\n" ); document.write( "x=-2y
\n" ); document.write( "

Algebra.Com's Answer #38178 by funmath(2933)\"\" \"About 
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Solve the system
\n" ); document.write( "L1) 3x+4y=-2
\n" ); document.write( "L2) x=-2y
\n" ); document.write( "Substitute -2y in for x in L1) and solve for y:
\n" ); document.write( "3(-2y)+4y=-2
\n" ); document.write( "-6y+4y=-2
\n" ); document.write( "-2y=-2
\n" ); document.write( "-2y/-2=-2/-2
\n" ); document.write( "y=1
\n" ); document.write( "Substitute 1 in for y in L2):
\n" ); document.write( "x=-2(1)
\n" ); document.write( "x=-2
\n" ); document.write( "The solution is (x,y)=(-2,1)
\n" ); document.write( "Happy Calculating!!!
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