document.write( "Question 605623: locate the center, foci, vertices, and ends of the latera recta of the ellipse. find the equation of the ellipse satisfying the given conditions.
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document.write( "find the equation for the specified hyperbola center at the origin, latus rectum 64/3, eccentricity 5/3. pls graph it
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Algebra.Com's Answer #381764 by KMST(5328)![]() ![]() You can put this solution on YOUR website! EQUATION FOR THE HYPERBOLA: \n" ); document.write( "A hyperbola with the equation \n" ); document.write( "has an eccentricity of \n" ); document.write( " \n" ); document.write( "and a latus rectum of \n" ); document.write( "So from \n" ); document.write( "We also have \n" ); document.write( " \n" ); document.write( "Combining both equations: \n" ); document.write( " \n" ); document.write( "and then \n" ); document.write( " \n" ); document.write( "That gives us the equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "GRAPHING: \n" ); document.write( "With \n" ); document.write( " \n" ); document.write( "We also know that \n" ); document.write( " \n" ); document.write( "which tells us that the foci are at distance 10 from the center. \n" ); document.write( "And since the latus rectum is 64/3, there are points of the hyperbola, 32/3 above and below the foci. \n" ); document.write( "That gives us the location of the foci and 4 more points of the hyperbola \n" ); document.write( " \n" ); document.write( "Now, I would just connect the points of the hyperbola that I found with smooth curved arches ) ( that hug the asymptotes towards their ends. \n" ); document.write( " |