document.write( "Question 605623: locate the center, foci, vertices, and ends of the latera recta of the ellipse. find the equation of the ellipse satisfying the given conditions.
\n" ); document.write( "find the equation for the specified hyperbola center at the origin, latus rectum 64/3, eccentricity 5/3. pls graph it
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Algebra.Com's Answer #381764 by KMST(5328)\"\" \"About 
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EQUATION FOR THE HYPERBOLA:
\n" ); document.write( "A hyperbola with the equation \"x%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1\"
\n" ); document.write( "has an eccentricity of
\n" ); document.write( "\"e=sqrt%281%2Bb%5E2%2Fa%5E2%29\"
\n" ); document.write( "and a latus rectum of \"2%2Al=2b%5E2%2Fa\"
\n" ); document.write( "So from \"2b%5E2%2Fa=64%2F3\" we get \"b%5E2%2Fa=32%2F3\"
\n" ); document.write( "We also have
\n" ); document.write( "\"sqrt%281%2Bb%5E2%2Fa%5E2%29=5%2F3\" --> \"1%2Bb%5E2%2Fa%5E2=25%2F9\" --> \"b%5E2%2Fa%5E2=25%2F9-1\" --> \"b%5E2%2Fa%5E2=16%2F9\" --> \"b%2Fa=4%2F3\"
\n" ); document.write( "Combining both equations:
\n" ); document.write( "\"%28b%5E2%2Fa%29%2F%28b%2Fa%29=%2832%2F3%29%2F%284%2F3%29\" --> \"highlight%28b=8%29\"
\n" ); document.write( "and then
\n" ); document.write( "\"b%2F%28b%2Fa%29=8%2F%284%2F3%29=8%2A3%2F4\" --> \"highlight%28a=6%29\"
\n" ); document.write( "That gives us the equation:
\n" ); document.write( "\"x%5E2%2F6%5E2-y%5E2%2F8%5E2=1\" or \"highlight%28x%5E2%2F36-y%5E2%2F64=1%29\"
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\n" ); document.write( "GRAPHING:
\n" ); document.write( "With \"a=6\" and \"b=8\", we can draw that box that gives us the vertices and the asymptotes.
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\n" ); document.write( "We also know that
\n" ); document.write( "\"e=c%2Fa\" so \"5%2F3=c%2F6\" --> \"highlight%28c=10%29\"
\n" ); document.write( "which tells us that the foci are at distance 10 from the center.
\n" ); document.write( "And since the latus rectum is 64/3, there are points of the hyperbola, 32/3 above and below the foci.
\n" ); document.write( "That gives us the location of the foci and 4 more points of the hyperbola
\n" ); document.write( " I have the foci (green circles) and six points of the hyperbola (blue circles marking the vertices and the ends of the latera recta).
\n" ); document.write( "Now, I would just connect the points of the hyperbola that I found with smooth curved arches ) ( that hug the asymptotes towards their ends.
\n" ); document.write( "\"graph%28300%2C300%2C-25%2C25%2C-25%2C25%2C4x%2F3%2C-4x%2F3%2Cx%5E2%2F36-y%5E2%2F64%3E1%29\"
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