document.write( "Question 605684: Write the following expression as a sum and/or difference of logarithms
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Algebra.Com's Answer #381761 by lawdej(58)\"\" \"About 
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log((cube root x^2+1)/(x^2-1))
\n" ); document.write( "=log(cube root x^2+1)-log(x^2-1)=log(cube root x^2+1)-log((x-1)(x+1))
\n" ); document.write( "=log(cube root x^2+1)-(log(x-1)+log(x+1))
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