document.write( "Question 605488: Kathryn drove her rig 3 hours before dawn and 4 hours after dawn. Her average speed was 6 miles per hour more in the dark and she covered 410 miles altogether. What was her speed after dawn in miles per hour? \r
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Algebra.Com's Answer #381711 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Kathryn drove her rig 3 hours before dawn and 4 hours after dawn. Her average speed was 6 miles per hour more in the dark and she covered 410 miles altogether. What was her speed after dawn in miles per hour?
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\n" ); document.write( "Before dawn DATA:
\n" ); document.write( "time = 3 hrs ; rate = x+6 mph ; distance = 3x+18 miles
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\n" ); document.write( "After dawn DATA:
\n" ); document.write( "time = 4 hrs ; rate = x mph ; distance = 4x miles
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\n" ); document.write( "Equation:
\n" ); document.write( "3x+18 + 4x = 410 miles
\n" ); document.write( "7x = 392 miles
\n" ); document.write( "x = 56 mph (speed after dawn)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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