document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=605449>Question 605449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The natural logarithm function<BR>\n" );
document.write( "write in exponential form\r<BR>\n" );
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document.write( "ln 1/e^2= -2\r<BR>\n" );
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document.write( "the example I have been trying to use is  log base b a=n  is rewritten as b^n=a\r<BR>\n" );
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document.write( "I can't tell in this problem if the e that is squared is the one that is the base.  <BR>\n" );
document.write( "if not then substituting I would get <BR>\n" );
document.write( "e^-2= 1/e^2<BR>\n" );
document.write( "  is this the answer or can I do more to it?\r<BR>\n" );
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document.write( "Thank you<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381693 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write in exponential form <BR>\n" );
document.write( "ln 1/e^2= -2 <BR>\n" );
document.write( "exponential form: base(e) raised to log of number(-2)=number(1/e^2)<BR>\n" );
document.write( "e^-2=(1/e^2) </SPAN>\n" );
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