document.write( "Question 605412: log(6x+3)=1+log(x-6) \n" ); document.write( "

Algebra.Com's Answer #381684 by stanbon(75887) $\"\"$ $\"About$

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log(6x+3)=1+log(x-6)
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\n" ); document.write( "log(6x+3) - log(x-6) = 1
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\n" ); document.write( "log[(6x+3)/(x-6)] = 1
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\n" ); document.write( "(6x+3)/(x-6) = 10
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\n" ); document.write( "6x+3 = 10x-60
\n" ); document.write( "4x = 63
\n" ); document.write( "x = 63/4
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "================= \n" ); document.write( "

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