document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=605329>Question 605329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hoe much soil containing 45% sand do you need to add to 1ft(cubed) of soil containing 15% sand in order to make a soil containing 35% sand? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381673 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much soil containing 45% sand do you need to add to 1ft(cubed) of soil containing 15% sand in order to make a soil containing 35% sand?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "sand + sand = sand<BR>\n" );
document.write( "0.45x + 0.15*1 = 0.35(x+1)<BR>\n" );
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document.write( "45x 15*1 = 35x + 35*1<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "10x = 20<BR>\n" );
document.write( "x = 2 cu. ft (amt of 45% soil needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );