document.write( "Question 605340: find dy/dx
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Algebra.Com's Answer #381647 by jim_thompson5910(35256)\"\" \"About 
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y = 2*ln(x) + 6*log(2,x)\r
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\n" ); document.write( "\n" ); document.write( "dy/dx = d/dx( 2*ln(x) + 6*log(2,x) )\r
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\n" ); document.write( "\n" ); document.write( "dy/dx = d/dx( 2*ln(x) ) + d/dx( 6*log(2,x) )\r
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\n" ); document.write( "\n" ); document.write( "dy/dx = 2*d/dx( ln(x) ) + 6*d/dx( log(2,x) )\r
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\n" ); document.write( "\n" ); document.write( "dy/dx = 2*(1/x)+ 6*d/dx( ln(x)/ln(2) )\r
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\n" ); document.write( "\n" ); document.write( "dy/dx = 2*(1/x)+ 6*(1/ln(2))*d/dx( ln(x) )\r
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\n" ); document.write( "\n" ); document.write( "dy/dx = 2*(1/x)+ 6*(1/ln(2))*(1/x)\r
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\n" ); document.write( "\n" ); document.write( "dy/dx = 2/x+ 6/(x*ln(2))\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"%28dy%29%2F%28dx%29+=+2%2Fx%2B+6%2F%28x%2Aln%282%29%29\"
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