document.write( "Question 605219: a long distance runner begins her workout by jogging to the park, a distance of 12 miles she then jogs home at the same speed but along a different route this trip is 18 miles and her time is one hour longer. find her jogging speed. \n" ); document.write( "
Algebra.Com's Answer #381577 by alicealc(293)\"\" \"About 
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speed = distance/time\r
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\n" ); document.write( "\n" ); document.write( "let the runner jogs to the park for t hours, with the distance of 12 miles
\n" ); document.write( "so the runner's speed = 12/t mph\r
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\n" ); document.write( "\n" ); document.write( "when she jogs home at the same speed, her trip is 18 miles and her time is one hour longer:
\n" ); document.write( "\"12%2Ft=18%2F%28t%2B1%29\"
\n" ); document.write( "12 * (t + 1) = 18 * t
\n" ); document.write( "12t + 12 = 18t
\n" ); document.write( "12 = 18t - 12t
\n" ); document.write( "12 = 6t
\n" ); document.write( "t = 12/6 = 2
\n" ); document.write( "the runner's speed = 12/t = 12/2 = 6 mph\r
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\n" ); document.write( "\n" ); document.write( "so, the runner's speed is 6 miles per hour\r
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