document.write( "Question 605112: A car passes a landmark on a highway traveling at a constant rate of 45 kilometers per hour. An hour later, a second car passes the same landmark traveling in the same direction at 60 kilometers per hour. How much time after the second car passes the landmark will it overtake the first car? \n" ); document.write( "
Algebra.Com's Answer #381559 by mananth(16946)![]() ![]() You can put this solution on YOUR website! the distance traveled by both is same when one catches up with the other. \n" ); document.write( "Let them meet at distance x \n" ); document.write( "Car I speed= 45 mph \n" ); document.write( "Car II speed= 60 mph \n" ); document.write( " \n" ); document.write( "Time difference between the the two when they cross landmark = 1.00 hour \n" ); document.write( " \n" ); document.write( "Time taken by Car I = X / 45 \n" ); document.write( "Time taken by Car II = X / 60 \n" ); document.write( " \n" ); document.write( "X / 45 - X / 60 = 1 \n" ); document.write( " \n" ); document.write( "LCD - 180 \n" ); document.write( "Multiply equation by 180 \n" ); document.write( "180/45x-180/60x=1*180 \n" ); document.write( "4 x - 3 x = 180 \n" ); document.write( "1 x = 180 \n" ); document.write( "/ 1 \n" ); document.write( "x= 180 miles \n" ); document.write( "Car II speed= 60 mph \n" ); document.write( "Distance = 180 miles \n" ); document.write( "Time taken = 180 / 60 \n" ); document.write( "Time taken = 3 hour \n" ); document.write( " \n" ); document.write( "They will be together after 3 hours \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |