document.write( "Question 605073: Suppose that a chemistry student can obtain two acid solutions from the stock room. The first solution is 20% acid and the second solution is 45% acid. (The percentages are by volume.) How many milliliters of each solution should the student mix together to obtain 100 milliliters of 30% acid solution? \n" ); document.write( "
Algebra.Com's Answer #381534 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Acid solution I 20.00% ---------------- x ml
\n" ); document.write( "Acid solution II 45.00% ------ 100 - x ml
\n" ); document.write( "Mixture 30.00% ---------------- 100
\n" ); document.write( " 12
\n" ); document.write( "20.00%x+45.00%(100-x)= 30.00% *100
\n" ); document.write( "20x+45 (100-x) =3000
\n" ); document.write( "20x+4500-45x=3000
\n" ); document.write( "20x-45x=3000-4500
\n" ); document.write( "-25x= -1500
\n" ); document.write( "/ -25
\n" ); document.write( "x=60 ml 20.00% Acid solution I
\n" ); document.write( "40 ml 45.00% Acid solution II
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\n" ); document.write( "m.ananth@hotmail.ca
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