document.write( "Question 605073: Suppose that a chemistry student can obtain two acid solutions from the stock room. The first solution is 20% acid and the second solution is 45% acid. (The percentages are by volume.) How many milliliters of each solution should the student mix together to obtain 100 milliliters of 30% acid solution? \n" ); document.write( "
Algebra.Com's Answer #381534 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Acid solution I 20.00% ---------------- x ml \n" ); document.write( "Acid solution II 45.00% ------ 100 - x ml \n" ); document.write( "Mixture 30.00% ---------------- 100 \n" ); document.write( " 12 \n" ); document.write( "20.00%x+45.00%(100-x)= 30.00% *100 \n" ); document.write( "20x+45 (100-x) =3000 \n" ); document.write( "20x+4500-45x=3000 \n" ); document.write( "20x-45x=3000-4500 \n" ); document.write( "-25x= -1500 \n" ); document.write( "/ -25 \n" ); document.write( "x=60 ml 20.00% Acid solution I \n" ); document.write( "40 ml 45.00% Acid solution II \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |