document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=605086>Question 605086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ok... So I have the angle of 25 degrees, and the height is 4.89 meters how do I find the horizontal length and/or the long side of the triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381532 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok... So I have the angle of 25 degrees, and the height is 4.89 meters how do I find the horizontal length and/or the long side of the triangle?<BR>\n" );
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document.write( "If the 25 degree angle is opposite the 4.89 height,<BR>\n" );
document.write( "tan(25) = 4.89/base<BR>\n" );
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document.write( "base = 4.89/tan(25) = 10.49 meters<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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