document.write( "Question 604615: A commitee of 9 is to be selected from 6 women and 8 men.in how many ways can this be done if the committee must contain at least 4 women? \n" ); document.write( "
Algebra.Com's Answer #381498 by scott8148(6628)\"\" \"About 
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there are 6C4 ways of selecting 4 women from 6\r
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\n" ); document.write( "\n" ); document.write( "there are 8C5 ways of selecting 5 men from 8\r
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\n" ); document.write( "\n" ); document.write( "so there are (6C4 * 8C5) ways of selecting a 4 woman committee\r
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\n" ); document.write( "\n" ); document.write( "there are 6C5 ways of selecting 5 women from 6\r
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\n" ); document.write( "\n" ); document.write( "there are 8C4 ways of selecting 4 men from 8\r
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\n" ); document.write( "\n" ); document.write( "so there are (6C5 * 8C4) ways of selecting a 5 woman committee\r
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\n" ); document.write( "\n" ); document.write( "there is one way of selecting 6 women from 6\r
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\n" ); document.write( "\n" ); document.write( "there are 8C3 ways of selecting 3 men from 8\r
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\n" ); document.write( "\n" ); document.write( "so there are 8C3 ways of selecting a 6 woman committee\r
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\n" ); document.write( "\n" ); document.write( "sum the three committee types for the answer
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