document.write( "Question 604902: pure acid is to be added to a 10% acid solution to obtain 90L of 51% solution. what amounts of each should be used?\r
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document.write( "how many liters of 100% pure acid should be used to make the solution?\r
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document.write( "how many liters of the 10% solution should be used in the mixture? \n" );
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Algebra.Com's Answer #381471 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! pure acid is to be added to a 10% acid solution to obtain 90L of 51% solution. what amounts of each should be used?\r \n" ); document.write( "\n" ); document.write( "how many liters of 100% pure acid should be used to make the solution?\r \n" ); document.write( "\n" ); document.write( "how many liters of the 10% solution should be used in the mixture? \n" ); document.write( "------------------ \n" ); document.write( "p + t = 90 (total solution) \n" ); document.write( "1*p = 0.1*t = 0.51*90 (total acid) \n" ); document.write( "------------- \n" ); document.write( "Can you finish it? \n" ); document.write( "----------- \n" ); document.write( "PS Always add the pure acid to the weaker solution, in case it splatters due to heat. Never pour the water, or weaker solution, into strong acid. \n" ); document.write( " \n" ); document.write( " |