document.write( "Question 604902: pure acid is to be added to a 10% acid solution to obtain 90L of 51% solution. what amounts of each should be used?\r
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Algebra.Com's Answer #381471 by Alan3354(69443)\"\" \"About 
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pure acid is to be added to a 10% acid solution to obtain 90L of 51% solution. what amounts of each should be used?\r
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\n" ); document.write( "\n" ); document.write( "how many liters of the 10% solution should be used in the mixture?
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\n" ); document.write( "p + t = 90 (total solution)
\n" ); document.write( "1*p = 0.1*t = 0.51*90 (total acid)
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\n" ); document.write( "PS Always add the pure acid to the weaker solution, in case it splatters due to heat. Never pour the water, or weaker solution, into strong acid.
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