document.write( "Question 604674: The length of a rectangle is 5 centimeters less than two times its width. If the area is
\n" ); document.write( "42 square centimeters, what is the length and width? thank you!!
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Algebra.Com's Answer #381445 by alicealc(293)\"\" \"About 
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length= L
\n" ); document.write( "width = W\r
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\n" ); document.write( "\n" ); document.write( "L = 2W - 5
\n" ); document.write( "Area = length * width
\n" ); document.write( "42 = (2W - 5)*W
\n" ); document.write( "\"42+=+2W%5E2+-+5W\"
\n" ); document.write( "\"0+=+2W%5E2+-+5W+-+42\"
\n" ); document.write( "0 = (2W + 7)*(W - 6)
\n" ); document.write( "2W + 7 = 0 or W - 6 = 0
\n" ); document.write( "2W = -7 or W = 6
\n" ); document.write( "W = -7/2 or W = 6
\n" ); document.write( "because the width can't be a negative number, we choose W = 6
\n" ); document.write( "L = 2W - 5 = 2 * 6 - 5 = 12 - 5 = 7\r
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\n" ); document.write( "\n" ); document.write( "so the length of the rectangle is 7 centimeters and the width is 6 centimeters\r
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