document.write( "Question 604777: In a survey of 1,000 elders, 56% of them have been hospitalized before. Of those who have been
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document.write( "hositalized before, 54% have insurance. Of those never hospitalized before, 32% do not have
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document.write( "insurance. What is the probability that an elder selected at random has insurance? \n" );
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Algebra.Com's Answer #381417 by alicealc(293) ![]() You can put this solution on YOUR website! Elders who have been hospitalized = 56% \n" ); document.write( "Elders who have never been hospitalized = 100% - 56% = 44%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Elders who have been hospitalized and have insurance = 54% * 56% = 54/100 * 56% = 30.24%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Elders who have never been hospitalized and do not have insurance = 32% * 44% = 32/100 * 44% = 14.08% \n" ); document.write( "Elders who have never been hospitalized and have insurance = 44% - 14.08% = 29.92%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, the probability that an elder has insurance = 30.24% + 29.92% = 60.16% \n" ); document.write( " \n" ); document.write( " |