document.write( "Question 604752: Graph the equation. Identify the vertices, foci, and asymptotes of the hyperbola. y^2/16-x^2/36=1 \n" ); document.write( "
Algebra.Com's Answer #381410 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Graph the equation. Identify the vertices, foci, and asymptotes of the hyperbola. \n" ); document.write( "y^2/16-x^2/36=1 \n" ); document.write( "** \n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis. \n" ); document.write( "Its standard form: (y-k)^2/a^2-(x-h)^2/b^2=1, (h,k)=(x,y) coordinates of center \n" ); document.write( "For given hyperbola: y^2/16-x^2/36=1 \n" ); document.write( "center: (0,0) \n" ); document.write( "a^2=16 \n" ); document.write( "a=√16=4 \n" ); document.write( "vertices:(0,0±a)=(0,0±4)=(0,-4) and (0,4) \n" ); document.write( ".. \n" ); document.write( "b^2=36 \n" ); document.write( "b=√36=6 \n" ); document.write( ".. \n" ); document.write( "c^2=a^2+b^2=16+36=52 \n" ); document.write( "c=√52≈7.2 \n" ); document.write( "foci: (0,0±c)=(0,0±7.2)=(0,-7.2) and (0,7.2) \n" ); document.write( ".. \n" ); document.write( "Asymptotes: \n" ); document.write( "slope=±a/b=±4/6=±2/3 \n" ); document.write( "equation of asymptotes: \n" ); document.write( "y=±2x/3 \n" ); document.write( ".. \n" ); document.write( "y=±(16+4x^2/9)^.5 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |