document.write( "Question 604741: Please list the steps to get from 9^sqr(x)=3^x to the solutions {0,4}. The answers are provided in my book but I am stuck at the step 2^sqr(x)=x. All help is appreciated. \n" ); document.write( "
Algebra.Com's Answer #381381 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"9%5Esqrt%28x%29\" = \"3%5Ex\"
\n" ); document.write( "9 = 3^2, therefore we can rewrite this to
\n" ); document.write( "\"3%5E%282sqrt%28x%29%29\" = \"3%5Ex\"
\n" ); document.write( "therefore
\n" ); document.write( "\"2sqrt%28x%29\" = x
\n" ); document.write( "Square both sides to get rid of the radical
\n" ); document.write( "4x = x^2
\n" ); document.write( "0 = x^2 - 4x
\n" ); document.write( "or
\n" ); document.write( "x^2 - 4x = 0
\n" ); document.write( "Factor
\n" ); document.write( "x(x-4) = 0
\n" ); document.write( "two solutions
\n" ); document.write( "x = 0
\n" ); document.write( "and
\n" ); document.write( "x = 4
\n" ); document.write( "
\n" );